Three particles lie in the xy plane. particle 1 has mass m1 = 6.7 kg and lies on the x-axis at x1 = 4.2 m, y1 = 0. particle 2 has mass m2 = 5.1 kg and lies on the y-axis at x2 = 0, y2 = 2.8 m. particle 3 has mass m3 = 3.7 kg and lies at the origin. what is the direction of the net gravitational force on particle 3, expressed as an angle counterclockwise from the +x-axis?

Explanation:

Given:

mass of first particle,

mass of second particle,

mass of third particle,

coordinate position of first particle in meters,

coordinate position of second particle in meters,

coordinate position of third particle in meters,

Now, gravitational force on particle 3 due to particle 1:

towards positive Y axis.

gravitational force on particle 3 due to particle 2:

towards positive X axis.

Now the net force

For angle in counterclockwise direction from the +x-axis

the answer is b

explanation:

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures