If a rainstorm drops 5 cm of rain over an area of 13 km2 in the period of 3 hours, what is the momentum (in kg · m/s) of the rain that falls in five seconds? assume the terminal velocity of a raindrop is 10 m/s. (enter the magnitude. the density of water is 1,000 kg/m3.)

To solve the problem it is necessary to apply the concepts related to Conservation of linear Moment.

The expression that defines the linear momentum is expressed as

P=mv

Where,

m=mass

v= velocity

According to our data we have to

v=10m/s

d=0.05m

Volume

t = 3hours=10800s

From the given data we can calculate the volume of rain for 5 seconds

Where,

It is the period of time we want to calculate total rainfall, that is

Through water density we can now calculate the mass that fell during the 5 seconds:

Now applying the prevailing equation given we have to

Therefore the momentum of the rain that falls in five seconds is

if they have a finite resultant

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force