You are 80 kg and you want to push over a player that is 100 kg with a force of 1200 n at 20 degrees above the horizontal. you both have a static friction coefficient of 0.95. if he is pushing back with 1200 n at 20 degrees below horizontal on you, will you accelerate backwards?

Explanation:

Whenever we want to discuss the motion of a body,we need to consider the forces acting on that body and not the force it is exerting on other bodies.

Let be the force exerted by the other player on you.

Horizontal force exerted by other player is where is the angle between the direction of force and horizontal.

Given,

So,the horizontal force is

Vertical force exerted is

Normal reaction force from ground is the sum of vertical force and my weight=

Let the coefficient of static friction be

given,

Maximum frictional force is

Since the maximum frictional force is greater than the horizontal force,I will not accelerate backwards.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2