Asolid uniform disk of diameter 3.20 m and mass 42 kg rolls without slipping to the bottom of a hill, starting from rest. if the angular speed of the disk is 4.27 rad/s at the bottom, how high did it start on the hill

The height attained by the disk on the hill is 3.57 m.

The given parameters;

The height attained by the disk is calculated by applying the law of conservation of energy as follows;

Thus, the height attained by the disk on the hill is 3.57 m.

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Height reached by the ball, h = 3.57 meters

Explanation:

It is given that,

Mass of the disk, m = 42 kg

Diameter of the disk, d = 3.2 m

Radius, r = 1.6 m

Angular speed of the disk,

The kinetic energy of the disk is equal to its potential energy. Using the conservation of energy as :

h = 3.57 meters

So, the solid disk will reach to a height of 3.57 meters.

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