Askidder dragging of 520 kg walk-through forest at a constant speed of 3.5 m/s. if the skidder is applying a force of 1850 n what is the coefficient of friction between the log and the ground

The coefficient of friction between the log and the ground is, μₓ = 0.3630

Explanation:

Given data,

The skidder dragging the mass, m = 520 kg

The acceleration of the mass, a = 3.5 m/s

The force applied by the skidder, Fₓ = 1850 N

The kinetic frictional force is given by,

                       Fₓ = μₓ η

                      μₓ = Fₓ / η

Where  μₓ - the coefficient of the kinetic friction  

            η is the normal force acting on the mass due to gravitational force.

                          η = mg

                              = 520 x 9.8

                               = 5096 N

Substituting the values in the above equation,

                           μₓ = 1850 N / 5096 N

                                = 0.3630

Hence, the coefficient of friction between the log and the ground is, μₓ = 0.3630

emily ruth's annual premium is $1058.50

step-by-step explanation:

emily ruth is a female of 27 years age purchasing 20 year endowment insurance with face value $25000.

from the given table,

for females, the age of a male 3 years younger should be used.

so, we have to check for 24 year male for 20 year endowment.

it is 42.34 for every $1000 face value.

for a face value of $25000,

it is 25 * 42.34 = $1058.50

∴ emily ruth's annual premium is $1058.50

c because the action was the roller coaster reaches bottom of hill (action) reaction would be blood tends to drain away from head

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