1. a rope attaches a tire to an overhanging tree limb. a girl swinging on the tire has a
centripetal acceleration of 3.0 m/s2. if the length of the rope is 2.1 m, what is the girl's
tangential speed?

2.51 m/s

Explanation:

Formula for Centripetal Acceleration

a_{c} =\frac{v^{2} }{r}

where v= velocity of the girl swinging through a rope  and

r=radius of the circle she is moving in ie. the length of the rope assuming its attached till the center of the tire of negligible dimension.

Given

m/

r=2.1 m

v=??(in m)

Plugging in the values

3 =\frac{v^{2} }{2.1}

=3 × 2.1

= 6.3

v=

v=2.5099 m/s ≈ 2.51 m/s

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