Aweightlifter is bench-pressing 710 n. he raises the weight 0.65m above his chest. how much work does he do with this lift?

The work done is 461.5 J.

Explanation:

According to Kinetics, the work done is calculated as the product of force which has done work, and the displacement it has imposed. Hence,

In the problem, the given data, F = 710 N and s = 0.65 m

By applying the given values to the work done equation, we get as follows,

The unit is same as the energy, work done defines when 1 N force acts in a 1 m distance along the force’s direction.