How much heat must be removed from 200 pounds of blanched vegetables at 189 degrees f to freeze them to a temperature of 22 degrees f? (the vegetables have a 60% water content and the specific heat of solid vegetables is 0.24 btu/lb f) heat = number btu

To solve this problem it is necessary to apply the concepts related to heat exchange in the vegetable and water.

By definition the exchange of heat is given by

where,

m = mass

c = specific heat

= Change in temperature

Therefore the total heat exchange is given as

Our values are given as,

Total mass is = 200lb ,however the mass of solid vegetable and water is given as,

Replacing at our equation we have,

Therefore the heat removed is 22411.2 Btu

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