Two-point charges with charges q1 = 3.0 x 10-6 c and q2 = 2.0 x 10-6 c are separated by a distance of 30cm. a third charge qo =4.0 x 10-6 c is placed between the initial two charges 10cm from q1. from coulomb’s law, the force exerted by q1 on qo is 10.8n and the force exerted by q2 on qo is 1.8n.

determine using a labelled diagram (a) the net electrostatic force acting on the charge qo. (b) what is the electric field (force per unit charge) at the location of the charge, qo due to the other two charges?

Wish i knew this to !

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge