A3.00-m rod is pivoted about its left end. a force of 7.80 n is applied perpendicular to the rod at a distance of 1.60 m from the pivot causing a ccw torque, and a force of 2.60 n is applied at the end of the rod 3.00 m from the pivot. the 2.60-n force is at an angle of 30.0o to the rod and causes a cw torque. what is the net torque about the pivot? (take ccw as positive.)

a. 26.4 n·m

b. 4.68 n·m

c. 8.58 n·m

d. -8.58 n·m

e. -16.4 n·m

The net torque about the pivot is and the answer is 'c'

c.

Explanation:

The torque is the force apply in a distance so it is the moment so depends on the way to be put it the signs so:

Now to find the net Torque is the summation of both torques

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.

true is the correct answer

hope i