The water stream strikes the inclined surface of the cart. determine the power produced by the stream if, due to rolling friction, the cart moves to the right with a constant velocity of 2 m/s. the discharge from the 50-mm-diameter nozzle is 0.04 m3/s. one-fourth of the discharge flows down the incline, and three-fourths flows up the incline. assume steady flow, all within the vertical plane.

Answer

given,

constant speed of cart on right side = 2 m/s

diameter of nozzle = 50 mm = 0.05 m

discharge flow through nozzle = 0.04 m³

One-fourth of the discharge flows down the incline

three-fourths flows up the incline

Power = ?

Normal force i.e. Fn acting on the cart

v is the velocity of jet

Q = A V

v = 20.37 m/s

u be the speed of cart assuming it to be u = 2 m/s

angle angle of inclination be 60°

now,

F n = 2295 N

now force along x direction

Power of the cart

P = F x v

P = 1987.52 x 20.37

P = 40485 watt

P = 40.5 kW

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr