Aparticle with charge q and kinetic energy ke travels in a uniform magnetic field of magnitude b. if the particle moves in a circular path of radius r, find expressions for its speed v and its mass m. (use any variable or symbol stated above as necessary.) (a) expression for its speed (do not use m in your answer.) v = (b) expression for its mass (do not use v in your answer.) m =

a)

b)

Explanation:

Given that

Charge = q

Magnetic filed = B

Radius = R

We know that kinetic energy KE

                   ----------1

m v² = 2 .KE            

The magnetic force F = q v B

Radial force

For uniform force these two forces should be equal

q v B R =m v²

q v B R =  2 .KE

Now put the velocity v in the equation

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this

the right answer is 0.3 meters per second