A5.00-g bullet is shot through a 1.00-kg wood block suspended on a string 2.00 m long. the center of mass of the block rises a distance of 0.38 cm. find the speed of the bullet as it emerges from the block if its initial speed is 450 m/s

395.6 m/s

Explanation:

Given

mass of bullet

mass of wood block

Length of string

Center of mass rises to an height of

initial velocity of bullet

let and be the velocity of bullet and block after collision

Conserving momentum

-------------1

Now after the collision block rises to an height of 0.38 cm

Conserving Energy for block

kinetic energy of block at bottom=Gain in Potential Energy

substitute the value of in equation 1