In a young’s double-slit experiment that uses electrons, the angle that locates the first-order bright fringes is θa = 4.0 × 10-4 degrees when the magnitude of the electron momentum is pa = 1.2 × 10-22 kg*m/s. with the same double slit, what momentum magnitude pb is necessary so that an angle of θb = 8.0 × 10-4 degrees locates the first-order bright fringes?

15.3 cos 65 degrees trig

i think its c if i'm wrong

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.