Amodel airplane of mass 1.2 kg is attached to a horizontal string and flies in a horizontal circle of radius 6.5 m, making 1.6 revolutions every 8 s. (the weight of the plane is balanced by the upward "lift" force of the air on the wings of the plane.) the accelaration due to the gravity is 9.81 m/s2 . find the speed of the plane. answer in units of m/s.

The speed of the model airplane is equal to 8.17 m/s.

Given the following data:

To determine the speed of the airplane:

First of all, we would determine the time period.

1.6 revs = 8 seconds

1 revs = X seconds

Cross-multiplying, we have:

Time period = 5 seconds.

Next, we would find the angular velocity:

Now, we can determine the speed of the airplane:

Speed = 8.17 m/s

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v=8.17 m/s

Explanation:

Given

mass of airplane

Radius of circle

1.6 revolution in 8 s  

i.e. 1 revolutions in 5 s

time period of 1 revolution is 5 s

and

where

Speed of plane

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//