Unpolarized light whose intensity is 1.46 w/m2 is incident on the polarizer in the drawing. (a) what is the intensity of the light leaving the polarizer? (b) if the analyzer is set at an angle of = 54.0° with respect to the polarizer, what is the intensity of the light that reaches the photocell?

0.73 W/m²

0.2522 W/m²

Explanation:

= Unpolarized light = 1.46 W/m²

= Analyzer angle = 54°

Light through first filter

The intensity of the light leaving the polarizer is 0.73 W/m²

After passing through analyzer

The intensity of the light that reaches the photocell is 0.2522 W/m²

an energy transformation flow diagram is shown

where is it ?