Amachine carries a 33.6 kg package from an initial position of r0 = (0.502 + 0.751 + 0.207) m at t0 = 0 s to a final position of r1 = (7.82 + 2.17 + 7.44) m at t1 = 11.9 s. the constant force applied by the machine on the package is f = (21.5 + 42.5 + 63.5) n.

The work done on the package by the machine's force is 676.94 J.

Explanation:

Given that,

Mass of package = 33.6 kg

Initial position

Final position

Final time = 11.9 s

Force

Suppose we need to find the work done on the package by the machine's force

We need to calculate the displacement

Using formula of displacement

Put the value into the formula

We need to calculate the work done

Using formula of work done

Hence, The work done on the package by the machine's force is 676.94 J.

the bal will not change its velocity.