Abaseball pitcher throws a ball horizontally at a speed of 34.0 m/s. a catcher is 18.6 m away from the pitcher. find the magnitude, in meters, of the vertical distance that the ball drops as it moves from the pitcher to the catcher. ignore air resistance.

To develop this problem, it is necessary to apply the concepts related to the description of the movement through the kinematic trajectory equations, which include displacement, velocity and acceleration.

The trajectory equation from the motion kinematic equations is given by

Where,

a = acceleration

t = time

= Initial velocity

= initial position

In addition to this we know that speed, speed is the change of position in relation to time. So

x = Displacement

t = time

With the data we have we can find the time as well

With the equation of motion and considering that we have no initial position, that the initial velocity is also zero then and that the acceleration is gravity,

Therefore the vertical distance that the ball drops as it moves from the pitcher to the catcher is 1.46m.

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answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.