Acubical water tank with edges measuring 10 feet in length is initially full of water. if the tank were then to lose water at a constant rate of 10 cubic feet per second, in how many seconds would the tank be full?

100 secs

Explanation:

edge of the cubical tank = 10 feet

volume of the cube is = edge^3

therefore volume = 10^3= 1000 cubic feet

discharge from the pipe Q= 10 cubic feet per second

time taken to fill the tank t= V/Q = 1000/10= 100 secs

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.