Abaseball is thrown at an angle of 29 relative to the ground at a speed of 24.3 m/s. the ball is caught 51.0463 m from the thrower. the acceleration due to gravity is 9.81 m/s2. how long is it in the air? answer in units of s.

T = 2.4 s

Explanation:

given,

angle at which ball is thrown = 29°

speed relative to ground = 24.3 m/s

ball is caught at a distance = 51.0463

acceleration due to gravity = 9.8 m/s²

time for which ball was in the air = ?

now,

velocity of ball in x-direction

V_x =  v cos θ

V_x =  24.3 x cos 29°

V_x = 21.25 m/s

velocity in y direction

V_y =  v sin θ

V_y =  24.3 x sin 29°

V_y = 11.78 m/s

distance on the ground when ball will reach maximum height

x = 51.0463/2 = 25.52 m

at top most point velocity is equal to zero

time for which the ball was in air

v = u + a t

0 = 11.78 - 9.8 t

t = 1.20

this time is taken to travel half distance

total time = 2 x 1.20

T = 2.4 s

time for which ball was in air is T = 2.4 s

think about the oscillation of the toy shown in the video. when the toy is at the highest point of its motion, its velocity is zero and its acceleration is negative.

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step-by-step explanation: