9. a 1.80 kg block slides on a rough horizontal surface. the block hits a spring with a speed of 2.5m/s and compresses it a distance of 13cm before coming to rest. if the coefficient of kinetic friction between the block and surface is 0.560, what is the force constant of the spring? (use non-conservative energy principle to solve this problem)

k = 513.7 N/m

Explanation:

given,

mass of block = 1.80 Kg

Speed at which block hit spring = 2.5 m/s

compression length(x) = 0.13 m

coefficient of kinetic friction = 0.56

force constant of the spring =?

non conservative work done by the frictional force

W = -f d

W = - μ mg x...............(1)

non conservation work done

Work done is change in energy

.........(2)

equating equation (1) and (2)

k = 513.7 N/m

force constant for spring is equal to k = 513.7 N/m

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