Ahorse of mass 242 kg pulls a cart of mass 224 kg. the acceleration of gravity is 9.8 m/s 2 . what is the largest acceleration the horse can give if the coefficient of static friction between the horse’s hooves and the road is 0.894? answer in units of m/s 2 .

To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as

F = ma

Where,

m= Mass

a = Acceleration

At the same time the frictional force can be defined as,

Where,

Frictional coefficient

N = Normal force (mass*gravity)

Our values are given as,

By condition of Balance the friction force must be equal to the total net force, that is to say

Re-arrange to find acceleration,

Therefore the acceleration the horse can give is

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this