Physics, 29.11.2019 04:31 mccdav5100

If a non-human civilization were to develop on saturn's largest moon, titan, its scientists might well develop a temperature scale based on
the properties of methane, which is much more abundant on the surface than water. methane freezes at -182.6°c on titan, and boils at
-155.2°c taking the boiling point of methane as 100.0°m (degrees methane) and its freezing point as 0°m, what temperature on the
methane scale corresponds to the absolute zero point of the kelvin scale?

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Answer from: briansalazar17

$-330.47 \°M$

Explanation:

Let's begin by explaining that the relation between the Celsius scale and Kelvin scale is:

$\°C +273.15=K$

This means the absolute zero point of the Kelvin scale is $0 K=-273.15 \°C$

Keeping this in mind, we have the freezing point and boling point of Methane as:

Freezing point: $0 \°M=-182.6 \°C=90.55 K$

Boiling point: $100 \°M=-155.2 \°C=117.95 K$

According to this, there is a linear relation between the methane scale ( $\°M$ ) and the Kelvin scale in the form:

$T=a+bt_{M}$ (1)

Where:

is the temperature in Kelvin

$t_{M}$ is the temperature in degrees Methane

Firstly, we need to find the value of and with the two given points ( 90.55 K and 117.95 K ):

When T=90.55 and $t_{M}=0$ :

90.55=a+b(0)

a=90.55 (2)

When T=117.95 and $t_{M}=100$ :

117.95=90.55+b(100)

b=0.274 (3)

Now we have the linear equation:

$T=90.55+0.274t_{M}$ (4)

Isolating $t_{M}$ :

$t_{M}=\frac{T-90.55}{0.274}$ (5)

Evaluating for T=0 K :

$t_{M}=\frac{0-90.55}{0.274}$ (6)

Finally:

$t_{M}=-330.47 \°M$

This means $0 K=-330.47 \°M$

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

Answer from: Quest

ya te mando la respuesta

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