Physics, 29.11.2019 23:31 jaylanmahone223

The bob of a pendulum has 600 j of kinetic energy at the bottom of its swing. as the bob rises to a height of 4 m above the bottom, it gains 400 j of potential energy. how much kinetic energy does it have at this point?

200 j

300 j

400 j

1000 j

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Answer from: ceibrione1

The K.E of the pendulum is, K.E = 200 J

Explanation:

Given data,

The kinetic energy of the bob of the pendulum at the bottom, K.E = 600 J

The potential energy at the height 4 m, P.E = 400 J

According to the conservation of energy, the total energy of the mechanical system should be conserved.

At the bottom of the swing, the entire mechanical energy of the pendulum is purely kinetic. Therefore the total energy

E = P.E + K.E

= 0 + 600 J

= 600 J

Therefore, the total energy of the system, E = 600 J

At height 4 m, the total energy of the system remains the same.

Therefore,

600 J = 400 J + K.E

K. E = 600 J - 400 J

= 200 J

Hence, the K.E of the pendulum is, K.E = 200 J

Answer from: Quest

r = ρ x length / area

ρ = r x area / length

ρ is in ohm-meters

in basic units, it is m³kg/s³a²

i think this is it.

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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