My notes a flat loop of wire consisting of a single turn of cross-sectional area 7.80 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 t to 3.20 t in 1.02 s. what is the resulting induced current if the loop has a resistance of 1.30 ?

0.00158 A

Explanation:

A = Area of loop = 7.8 cm²

= Final magnetic field = 3.2 T

= Initial magnetic field = 0.5 T

R = Resitance =

The emf is given by

The current is given by

The resulting induced current in the loop is 0.00158 A

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.