Anoninverting op-amp circuit with a gain of 96 v/v is found to have a 3-db frequency of 8 khz. for a particular system application, a bandwidth of 32 khz is required. what is the highest gain available under these conditions?

Explanation:

given,

op-amp circuit with a gain of = (Av₁) = 96 V/V

Band width  = (Bw₁) = 8 kHz

Required bandwidth(Bw₂) = 32 kHz

Highest gain available =(Av₂) = ?

For the given system Bandwidth product is constant

                           Av₁ Bw₁ = Av₂ Bw₂

                           96 x 8 = Av₂ x 32

the highest gain available under these conditions

0.11 m/s and 0.28 m/s should be correct

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