You are the science officer on a visit to a distant solar system. prior to landing on a planet you measure its diameter to be 1.8×107m and its rotation period to be 22.3 hours . you have previously determined that the planet orbits 2.2×1011m from its star with a period of 397 earth days. once on the surface you find that the free-fall acceleration is 12.2m/s2. what is the mass of the planet?

what is the mass of the star?

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

-reverse card

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

k2s for potassium sulphide