Unpolarized light of intensity 800 w/m2 is incident on two ideal polarizing sheets that are placed with their transmission axes perpendicular to each other. an additional polarizing sheet is then placed between the two, with its transmission axis oriented at 30∘ to that of the first. what is the intensity of the light passing through the stack of polarizing sheets? (express your answer to two significant figures.)

75 W/m²

Explanation:

= Unpolarized light intensity = 800 W/m²

= Angle between filters = 30°

Intensity of light after passing through first polarizer

Intensity of light after passing through second polarizer

Intensity of light after passing through third polarizer

The intensity of the light passing through the stack of polarizing sheets is 75 W/m²

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

it's a b and