A500kg car skids to a stop at a traffic light, leaving behind a 18.25m skid mark as it comes to a rest. assuming that the car is travelling at 14.5m/s and only the friction from the tires on the roadway stop the vehicle. find the coefficient of friction

Coefficient of friction will be 0.587

Explanation:

We have given mass of the car m = 500 kg

Distance s = 18.25 m

Initial velocity of the car u = 14.5 m/sec

As the car finally stops so final velocity v = 0 m/sec

From second equation of motion

We know that acceleration is given by

So coefficient of friction will be 0.587

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

a displacement distance is size of displ