Aperson with mass mp = 71 kg stands on a spinning platform disk with a radius of r = 1.62 m and mass md = 193 kg. the disk is initially spinning at ω = 1.8 rad/s. the person then walks 2/3 of the way toward the center of the disk (ending 0.54 m from the center). 1)what is the total moment of inertia of the system about the center of the disk when the person stands on the rim of the disk?

439.587 kgm²

Explanation:

= Mass of person = 71 kg

R = Radius of platform = 1.62 m

= Mass of disc = 193 kg

The moment of inertia of the system is given by

The total moment of inertia of the system about the center of the disk when the person stands on the rim of the disk is 439.587 kgm²

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer