An proton-antiproton pair is produced by a 2.20 × 10 3 2.20×103 mev photon. what is the kinetic energy of the antiproton if the kinetic energy of the proton is 161.90 mev? use the following joules-to-electron-volts conversion 1ev = 1.602 × 10-19 j. the rest mass of a proton is 1.67 × 10 − 27 1.67×10−27 kg.

To solve this problem it is necessary to apply the concepts related to Kinetic Energy in Protons as well as mass-energy equivalence.

By definition the energy in a proton would be given by

The mass-energy equivalence is given as,

Here,

c = Speed of light

The energy of the photon is given by,

Replacing with our values,

Therefore we can calculate the kinetic energy of an anti-proton through the energy total, that is,

Therefore the kinetic energy of the antiproton if the kinetic energy of the proton is 161.90 MeV would be 161.5MeV

answer: decibel

explanation:

resonant frequency