An infinite plane of charge has a surface charge density of 5 µc/m2 . how far apart are the equipotential surfaces whose potentials differ by 105 v? the permittivity of free space is 8.85 × 10−12 c 2 /n · m2 . answer in units of mm.

Distance in mm will be 0.3718 mm

Explanation:

We have given charge surface charge density

We know that electric field due to surface charge density is given by

We have given potential difference V = 105 volt

We know that potential difference is given by

So