Determine the ratio of the flow rate through capillary tubes a and b (that is, qa/qb).

the length of a is twice that of b, and the radius of a is one-half that of b.

the pressure across both tubes is the same.

To solve this problem we can use the concepts related to the change of flow of a fluid within a tube, which is without a rubuleous movement and therefore has a laminar fluid.

It is sometimes called Poiseuille’s law for laminar flow, or simply Poiseuille’s law.

The mathematical equation that expresses this concept is

Where

P = Pressure at each point

r = Radius

Viscosity

l = Length

Of all these variables we have so much that the change in pressure and viscosity remains constant so the ratio between the two flows would be

From the problem two terms are given

Replacing we have to

Therefore the ratio of the flow rate through capillary tubes A and B is 1/32

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!