Asmall artery has a length of 0.95 × 10-3 m and a radius of 2.4 ×10-5 m .
randomized variablesl = 0.95 × 10-3 m
r = 2.4 ×10-5 m
p = 1.65 kpa
if the pressure drop across the artery is 1.65 kpa, what is the flow rate through the artery in mm3/s? (assume that the temperature is 37ºc, and the viscosity of blood at that temperature is 2.084 × 10-3 n⋅s/m2). sig. gif? tid=8c84-ec-3e-40-9751-12853
q=

That would be the corect answer hope this

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.