Auniform rod is 2 m long. the rod is pivoted about a horizontal, frictionless pin through one end. the rod is released from rest at an angle of 30 degrees above the horizontal.
what is the angular acceleration of the rod at the instant it is released?
the rotational inertia of the rod, in this case, can be calculated using inerita= 1/3 m l^2 where m is the mass of the rod and l is the length of the rod.

a. 4.7 rad/s^2
b. 6.9 rad/s^2
c. 6.4 rad/s^2
d. 5.6 rad/s^2
e. 4.2 rad/s^2

i think the answer is b

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

friction

explanation:

they us to move forward and backwards