Ahollow ball with a diameter of 3.72 cm has an average density of 0.0841 g/cm3. what force must be applied to hold it stationary while it is completely submerged under water? (enter the magnitude in n, and select the direction from the options given.)

0.2158 N.

Explanation:

Given , The ball has diameter (d)=3.72 cm = 0.0372 m

radius(r) = d/2 = 1.86 cm = 0.0186 m

Average density= 0.0841 g/cm^3 = 84.1 kg/m^3

There are two forces acting on the ball.. i.e. The buoyancy force and weight of the ball.

The force required to completely submerged under water= Buoyancy force - Weight of ball

buoyancy force = volume×density of water×g

[ density of water = 1000 kg/m3]

=0.238 N

mass of ball = average density×Volume

=84.1×4.18×(0.018)^3

=0.0022262 kg

Weight of ball = mg = 0.00204×9.81 =0.02219 N

Required force = 0.238 - 0.02219 = 0.2158 N.

emily ruth's annual premium is $1058.50

step-by-step explanation:

emily ruth is a female of 27 years age purchasing 20 year endowment insurance with face value $25000.

from the given table,

for females, the age of a male 3 years younger should be used.

so, we have to check for 24 year male for 20 year endowment.

it is 42.34 for every $1000 face value.

for a face value of $25000,

it is 25 * 42.34 = $1058.50

∴ emily ruth's annual premium is $1058.50