Aforce f~ = fx ˆı + fy ˆ acts on a particle that
undergoes a displacement of ~s = sx ˆı + sy ˆ
where fx = 7 n, fy = −1 n, sx = 3 m, and
sy = 3 m.
find the work done by the force on the
particle.
answer in units of j.

find the angle between f~ and ~s.
answer in units of ◦

Work done is 18J

Explanation:

Force F = (Fx, Fy) and Displacement S = (Sx,Sy)

Fx=7N

Fy=-1N

Sx=3m

Sy=3m

F=(7,-1)N and S=(3,3)m

Work done is calculated by taking dot product of force and displacement vector

W=F·S

W=7×3 + (-1)×3

W=21+(-3)=18J

in physics zero. in muscle fatigue could be high

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.