A0.48 kg pool cue moving at 3.39 m/s hits the 0.22 kg cue ball that was a rest and the pool cue stops after the impact. what is the velocity of the cue ball after the impact (in m/s)?

7.39 m/s is the velocity of the cue ball after impact.

Explanation:

Given that,

We know that,  

If two objects collide then the “total momentum” before is equal to the “total momentum” after collision.  

Substitute the given values in the formula.

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west