An object that is initially at rest on a frictionless floor is struck by a flying rock with an impulse jfonox. what is the final momentum of the object?

jfonox

Explanation:

since impulse is the change in momentum given by

Impulse = Force x time = change in momentum

I = ft = mv-mu= m(v-u)= jfonox

since the object is initially at rest

u=0,

mv is the final momentum of the object

I =Ft = m(v - 0) = jfonox

mv= jfonox

this show that the final momentum of the object at rest is equal to the impulse received

if  any of the mass m, final velocity v or the impact force and the duration of impact of the object is known then we can find or quantify the final momentum.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s