Alight spring stretches 0.13 m when a 0.35 kg mass is hung from it. the mass is pulled down from this equilibrium position an additional 0.15 m and then released. determine the maximum speed of the mass.

v = 1.30 m/s

Explanation:

given,

mass hung = 0.35 Kg

spring stretched when load is hanged  (x)= 0.13 m

now,

weight of the mass attached = Kx

             m g = k x

             0.35 x 9.8 = k x 0.13

                k = 26.38 N/m

now, using conservation of energy

    v = 1.30 m/s

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6

what type of charge does it have? negative