Two forces act on a 42-kg object. one force has magnitude 65 n directed 59° clockwise from the positive x-axis, and the other has a magnitude 35 n at 32° clockwise from the positive y-axis. what is the magnitude of this object's acceleration?

a =  1.39 m/s²

Explanation:

given,

mass of object = 42 Kg

Force₁ = 65 N directed 59° clockwise from the positive x-axis

Force₂ = 35 N  32° clockwise from the positive y-axis

F_x = 65 cos 59° + 35 sin 32°

F_x = 33.48 + 18.55

F_x = 52.024 N

F_y = -65 sin 59° + 35 cos 32°

F_y = -55.72 + 29.68

F_y = -26.04 N

F = 58.19 N

F = ma

58.19  = 42 x a

a =  1.39 m/s²

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer