Aforce of 50 n is applied tangentially to the rim of a solid disk of radius 0.12 m. the disk rotates about an axis through its center and perpendicular to its face with a constant angular acceleration of 150 rad/s2. determine the mass of the disk.

m=3.7 Kg

Explanation:

Given that

F= 50 N

r= 0.12 m

α = 150 rad/s²

The moment of inertia of disk about center

I= 0.5 m r²

m=mass   , r=radius

The moment of inertia of disk about O

I' = 0.5 m r²+ m r²

I'=1.5 m r²

The torque produce by force F about O

τ = F x 2r

τ =2 F r

τ = 2 x 50 x 0.12 N.m

τ =12 N.m

We know that

τ = I' α

12 = 1.5 x m x  0.12² x 150

m=3.7 Kg

Mass of the disk m= 3.7 kg

none, its a machine

f=ma newton's second law 7x8=56n