Two point charges are located along the x axis: q1 = +5.9 μc at x1 = +4.2 cm, and q2 = +5.9 μc at x2 = −4.2 cm. two other charges are located on the y axis: q3 = +2.9 μc at y3 = +4.8 cm, and q4 = −8.2 μc at y4 = +6.9 cm. find the net electric field (magnitude and direction) at the origin.

Explanation:

In order to find the net electric field, we have to find the four electric fields and add them as vecotrs.

Hence, formula to calculate the electric field is as follows.

      E =

For the charge at x = 0.042 m               (as 1 m = 100 cm)

So,      

                        = N (toward the negative x direction)

For the charge at x = -0.042 m

                = N (toward the positive x direction)

For the charge at y = 0.048 m

                  = N (toward the negative y direction)

For the charge at y = 0.069 m

                     = N (toward the positive y)

Therefore, net x is calculated as follows.

The net x =

                = 0 N

The net y = N

                = N (positive y)

Total net E is found by the pythagorean theorem  as follows.

     E =

         = N

Thus, we can conclude that the net electric field (magnitude and direction) at the origin is N.

Explanation:

Given

Electric field is given by

Electric field due to and cancel out each other because they point in opposite direction in x-axis

so net Electric field will be because of and   towards negative Y axis

(away from q_3[/tex])

similarly (towards q_4[/tex])

an energy transformation flow diagram is shown

where is it ?

c. newton's third law of motion