Ametal rod with a length of 22.0cm lies in the xy-plane and makes an angle of 37.9 degrees with the positive x-axis and an angle of 52.1degrees with the positive y-axis. the rod is moving in the +x-direction with a speed of 6.80m/s . the rod is in a uniform magnetic field b =(0.170t)i^-(0.240t)j^-(0.0900t )k^.

what is the magnitude of the emf induced in the rod?

Induced emf in the rod is,

Explanation:

Given that,

Length of the rod, L = 22 cm = 0.22 m

Angle with x axis is 37.9 degrees with the positive x-axis and an angle of 52.1 degrees with the positive y-axis.

Velocity of the rod, v = 6.8i m/s

Magnetic field,

The formula for the emf induced in the rod is given by :

So, the magnitude of the emf induced in the rod is 0.08262 volts. Hence, this is the required solution.                                      

it is called kinetic energy