8toy car b is stationary and toy car a is pushed so
that it hits b at 1.2 m s on a smooth horizontal
plane (fig d). during the collision, toy car b
accelerates at 3 m s2 for 0.5 s on average. toy cars
a and b are of mass 3 kg and 1 kg respectively.
1.2 ms
fig d
(a) what is the average force acting on b by a
during the collision?
(b) what is the average force acting on a by b
during the collision?
ef(c) find the velocity of toy car a after the collision.

the body's situation won't change the forces are equal opposit and on the same body

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

i think the answer would be reserve.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .