Light with wavelength 633 nm is incident on a 3.00-μm-wide slit. part afind the angular width of the central peak in the diffraction pattern, taken as the angular separation between the first minima.

The angular width of the central peak is 24.2 degrees

Explanation:

The equation that describes the single-slit diffraction phenomenon is:

(1)

with a the width of the slit, the angular position of the minimum regarding the center of the screen where light is projected, m the order of the minimum and the wavelength. Solving (1) for with m=1 that is the first minimum:

See the figure below that the central peak is symmetric regarding the center of the screen, which implies that the angular width of the central peak is

see earlier