Two inductors are placed in a circuit in series with each other. inductor 1 has an inductance of 3.5e-3 h and inductor 2 has an inductance of 4.7e-6 h. anytime current is running through the inductors, what is the ratio of energy stored in inductor 1 compared to inductor 2? u1 is the energy in inductor 1 and u2 is the energy in inductor 2. group of answer choices u1 = 744.68 u2 u1 = 1.55e-3 u2 u1 = 25.36 u2 u1 = 3.93e-2 u2

ratio =  744.68

Explanation:

Inductance of first inductor L₁ = 3.5 x 10⁻³ H

Inductance of second inductor L₂ = 4.7 x 10⁻⁶ H

Let current i is flowing in both of them . This current produces magnetic field in them due to which magnetic energy is stored in them . Magnetic energy of an inductor

= 1/2 L i²

where L is inductance and i is current flowing in it

Magnetic energy U₁ in first inductor

U₁ = 1/2 x3.5 x 10⁻³ x i²

Magnetic energy U₂ in second inductor

U₂ =  1/2 x4.7 x 10⁻⁶ x i²

U₁ / U₂  = (1/2 x3.5 x 10⁻³ x i²) /  ( 1/2 x4.7 x 10⁻⁶ x i²                                                                                                                                                                                                                                                        3.5 x 10³ / 4.7

= 744.68

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2