A1730-n irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (a and b), each 1.30 m long and weighing 0.320 n . the center of gravity of this beam is one-third of the way along the beam from the end where wire a is attached. part a if you pluck both strings at the same time at the beam, what is the time delay between the arrival of the two pulses at the ceiling? (neglect the effect of the weight of the wires on the tension in the wires.)

Δt = .002s

Explanation:

        F1L1 -F2L2 = 0

       L2 = 2L/3 = 0.87 m

        F1 = 2F2

        F1 + F2 = 1730

        F1 = 1153.33 N ; F2 = 576.67 N

       m = 0.0326 kg

       mu =mass/length = 0.025

       v1=214.78 m/s

       v2= 151.87 m/s

        t=d/v;d=1.3m

        t1=.006s

        t2=.008s

        Δt = .002s

Source https://www.physicsforums.com/threads/irregular-beam-physics-homework.408573/

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000