Aproton moves in a circular path perpendicular to a constant magnetic field. if the field strength of the magnet is increased, does the diameter of the circular path increase, decrease, or remain the same?

The diameter of the circular path decrease

Explanation:

The magnitude of the magnetic force exerted on the proton is given by:

According to Newton's second law, this force is equal to the centripetal force. Therefore, we have:

Recall that . Replacing and solving for B:

Thus, the field stregth is inversely proportional to the radius of the path and since the radius is directly proportional to the diameter, if the field strength increases, the diameter decreases.

i think the answer is a, hope this is right, that would be my best guess.