Un cuerpo se mueve en línea recta segun la ecuación x=10+20t-4.9t2 (x está expresado en metros y t en segundos). ¿cuál es la longitud del camino recorrido al cabo de 3.0 segundos? porfa es para mañana

La longitud del camino recorrido es de 25.9 [m]

Explanation:

Se reemplaza el valor de tiempo en segundos en la ecuación dada de desplazamiento

x=10+20*(3) - 4.9*(3)^2

x= 25.9 [metros]

The length of the path traveled after 3.0 seconds is 25.9 meters

Explanation:

Given that,

A body moves in a straight line according to the equation,

........(1)

Here, x is in meters and t is in seconds

We need to find the length of the path traveled after 3.0 seconds. To find it, simply put the value of t as 3 seconds in equation (1).

So, the length of the path traveled after 3.0 seconds is 25.9 meters. Hence, this is the required solution.

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27